(3x^2-2x-3/2x^2)^2

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Solution for (3x^2-2x-3/2x^2)^2 equation: 


x in (-oo:+oo)

(3*x^2-((3/2)*x^2)-(2*x))^2 = 0

(3*x^2+(-3/2)*x^2-2*x)^2 = 0

(3/2*x^2-2*x)^2 = 0

3/2*x^2-2*x = 0

x*(3/2*x-2) = 0

3/2*x-2 = 0 // + 2

3/2*x = 2 // : 3/2

x = 2/3/2

x = 4/3

x*(x-4/3) = 0

x^2*(x-4/3)^2 = 0

( x-4/3 )

x-4/3 = 0 // + 4/3

x = 4/3

( x )

x = 0

x in { 4/3, 4/3, 0, 0 }

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